How many 7 card hands are possible if all the jacks must be in the hand?

So you have 52*51*50 possibilities, which is 132,600 possibilities.

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How many 7 card hands will consist of exactly 4 hearts and 3 clubs?

How many poker hands are there that contain exactly a 7? straights when the 7-card hand has 7 distinct ranks. sets of 6 distinct ranks corresponding to straights. Note this means there must be a pair in such a hand. Abstract: hand number Probability straight flush 41,584 .00031 4-of-a-kind 224,848 .0017 full house 3,473,184 .026 flush 4,047,644 .030 5 more rows ?

Also, which of the following can be probability of an event?

Explanation: An event's probability cannot be less than one, nor can it be greater than one. Which of the following Cannot be the probability of an event *? We know that the probability of an event E lies in between 0 and 1, that is, 0 ? P(E) ? 1 and it cannot be less than 0 and greater than 1. So, option (B) - 1.5 cannot be the probability of an event because it is negative.

Consequently, when drawing a random card from a deck of cards what is the probability of drawing either a four of hearts or a five of hearts?

Adding up the probability of getting hearts OR 5s, you have 13/52 + 3/52 = 16/52. You can reduce this fraction to 4/13. So that is your probability of drawing a heart or a 5.