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What's the probability of drawing a 7 in a deck of cards?

I am assuming that Jacks, Queens and Kings are face cards, but not Aces. So the deck contains 4 of each denomination, including 4 each of 7s, Jacks, Queens and Kings. The probability of drawing one of these is 16/52 = 4/13, about 30.77%.

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What is the probability of drawing 3 cards at random which are all aces if each card is replaced between each drawing?

There is a chance of drawing an ace. Each time, that is the probability if the ace is put back in the deck. The probability of drawing three ace in a row is 1/6.

Consequently, what is the probability of hearts?

Originally Answered: What are the odds in favor of drawing a heart from an ordinary deck of cards? One in four. There are 52 cards, four suites. You have a 25 percent chance in drawing a heart excluding jokers. What is the probability of drawing 2 hearts without replacement?

Keeping this in consideration, what is probability of drawing a club from a well shuffled pack of 52 cards?

Hence, the probability of drawing a club is 13/52 = 1/4. What's the probability that you draw 2 clubs from a deck of cards if you don't put the rst card back in without replacement )? Answer: 13/17. If the first card is a Club, then the second MUST be NOT Club.

What is the probability of first drawing the ace of spades and then drawing any of the three remaining aces from a 52 card pack?

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Then, what is the probability of drawing 4 of clubs?

A deck of cards consists of 52 different cards. Only 1 card is both a 4 and a club. Therefore the probability of drawing a 4 of clubs is 1/52. How many 5 of hearts are in a deck of cards? Originally Answered: How many 5s are in a deck of cards? A deck of cards consists of 13 cards in each of four suits for a total of 52. As there are four suits and every suit includes one 5, there are four 5s.

Accordingly, what is the probability of getting a 5 from a deck of 52 cards?

This can be done in 26C5 ways. Picking 5 red cards from out of the 52 cards is called as the desired event E. So n(E) = 26C5. Hence the probability of getting 5 red cards out of a deck of 52 = n(E)/n(S) = 26C5/52C5.

By Janis

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